Question

The sum of first n term of an AP is given by Sn=2n^2+3n.find the sixteen term of the AP

Answer 1

Hi sonam

Here is your answer

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#jerri

Answer 2

Given Sum of N terms = 2n²+3n

Sum of 1 terms = first term = 2(1²)+3(1)=2+3=5 .

First difference = a = 5

Sum of 2 terms = 2(2²)+3(2)=8+6=14

Second term = 14 - 5 = 9

Now Common difference = d = 9-5=4

Now Sixteen term = a + (n - 1) d

= 5 + ( 16 - 1 ) 4

= 5 + 15 ( 4 )

= 5 + 60

= 65.

Therefore ,The sixteenth term of the A.P is 65 whose sum of n terms = 2n²+3n .