the sum of first n term of an ap is given by SN equals to 2n2 + 3n and find the 16 term of the AP
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a16
= S16 -S15
= [2 × (16)^2 +3 × 16] -[2×(15)^2 + 3×15]
=[2× 256 +48] - [2×225 +45]
= [ 512 + 48] - [ 450 + 45]
= 560 - 495
= 85
hope it helps
= S16 -S15
= [2 × (16)^2 +3 × 16] -[2×(15)^2 + 3×15]
=[2× 256 +48] - [2×225 +45]
= [ 512 + 48] - [ 450 + 45]
= 560 - 495
= 85
hope it helps
Ujjwalgujral:
Thanks
ur welcome
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