The sum of first n terms of an A.P. is 5n – n². Find the nth term of this A.P.
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an = 6-2n
Step-by-step explanation:
(i) Given: The sum of first n terms of an A.P. is 5n – n²
Find: nth term of this A.P.
Now Sum = 5n – n²
S1 = 5(1) -(1)² = 4 = a1
S2 = 5(2) -4 = 6
S2 - S1 = a2 = 2
So d = 2-4 = -2
We have a = 4, d = -2
an = a + (n-1)d
= 4 + (n-1)(-2)
= 4 -2n +2
an = 6-2n
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