The sum of first n terms of an AP is 3n2-4n. Determine the AP and its 12th term. Also find its nth term.
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The value of 12th term is 65.
The value of nth term is 6n-7.
To find:
The value of 12th term of the given series and nth term.
Solution:
The sum of first n term is
The sum of first n - 1 term is
The difference of sum of (n – 1) and n will give us the value of
The value of
Putting the value of n = 1, 2 to determine the first value of the series and the common difference
Now to find the 12th term of series we use the formula of Arithmetic Progression:
Therefore, the value of twelfth term of series is 65, whereas the value of nth term of series is 6n-7.
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