The sum of first n terms of an ap is 3n2 + 4n. Find the nth term of this ap
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6
S1=3×1×1+4×1
=7=a1
S2=3×2×2+4×2
=12+8
=20
a2=S2-S1
=13
an=a+(n-1)d
common Difference=a2-a1
=6
an=7+6n-6
=1+6n
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3
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