Question

The sum of first n terms of an ap is 3n2+5n. Find the ap .hence find its 16th term

Answer 1

Solution is attached below in image

Answer 2

Sn = 3n^2 + 5n

Sn – 1 = 3(n – 1)^2 + 5(n – 1)

= 3(n^2 + 1 – 2n) + 5n – 5

= 3n^2 + 3 – 6n + 5n – 5

= 3n^2 – n – 2

an = Sn – Sn – 1 = 3n^2 + 5n – (3n^2 – n – 2)

= 6n + 2

AP is 8, 14, 20, ....................

a(16) => a + 15d = 8 + 15(6) = 98