The sum of first n terms of an ap is 5n^2+7n. The 10th term is ?
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so,
the 10th term is 102
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Step-by-step explanation:
sn 5n² + 7n
S, q. = 5(1)² + 7(1)
= 5+7 = 12
S, 2 = 5(2)² + 7(2)
20 + 14 = 34
S, 3 = 5(3)² + 7(3)
= 45 + 21 = 66
Ap = 12 , 34 - 12 = 22 , 66 - 34 = 32
Ap = 12 ., 22 , 32 ..
A = 12 , d = 22-12 = 10
A10 = a + (n-1)d
= 12 + (10 - 1) 10
= 12 + 90 = 102
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