the sum of first n terms of an ap is given by sn = 2n^2 + 5n find the nth term of ap
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the nth term is x..see if you dont tell the value it will be like that only
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Sn=2n2 +5 n
S1=2+5=8=t1=a
S2=2*4+5*2=18
Now T2=s2-s1=18-8=10
D=t2-t1=10-8=2
Now tn =a+(n-1) d
=8+(n-1)(2)
=8+2n-2
=6+2n
Hope it will be helpful to you dear......
S1=2+5=8=t1=a
S2=2*4+5*2=18
Now T2=s2-s1=18-8=10
D=t2-t1=10-8=2
Now tn =a+(n-1) d
=8+(n-1)(2)
=8+2n-2
=6+2n
Hope it will be helpful to you dear......
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