The sum of first n terms of an Ap is given by Sn=2n²+3n . Find the sixteenth term of the Ap
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16
Sn=2n^2+3n
Given:n=16
S16=2*(16)^2+3(16)
=2*256+48
=512+48
=560
Given:n=16
S16=2*(16)^2+3(16)
=2*256+48
=512+48
=560
Answered by
1
Answer:
560
Step-by-step explanation:
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