The sum of first n terms of an AP is given bySn = 2n2 + 3n . Find the sixteenth term of the AP.
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let n be 1
s1=2*1*2+3*1 sum of first term is first term only so
a=4+3=7
s2 =2*2*2 +3*2
a +a+d= 14
2*7 +d=14
d=0
so sixtheen term will be 7 only if d is 0
s1=2*1*2+3*1 sum of first term is first term only so
a=4+3=7
s2 =2*2*2 +3*2
a +a+d= 14
2*7 +d=14
d=0
so sixtheen term will be 7 only if d is 0
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