the sum of first n terms of an is 3n2 + 6n find the nth term of this ap
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Answered by
3
here a1 = a = s1 = 9
a1+ a2 =s2 = 24
a2 = 24-9=15
so d =a2-a1 = 15-9=6
nth term = a+ (n-1)d
=9+(n-1)6
=3+6n
a1+ a2 =s2 = 24
a2 = 24-9=15
so d =a2-a1 = 15-9=6
nth term = a+ (n-1)d
=9+(n-1)6
=3+6n
Answered by
3
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