the sum of first n terms of AP is given by Sn=2n square +3n. find the 16th term of ap
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given Sn = 2n^2 +3n
put n=1.
S1=2(1)^2+3(1)
=2+3=5
S1 = A1
A1 =5
put n as 16
S16= 2(16)^2+3(16)
= 512+48=560
S16 = n/2(a +An)
560=16/2(5+An)
560/8=5+An
70-5= An
An= 65
put n=1.
S1=2(1)^2+3(1)
=2+3=5
S1 = A1
A1 =5
put n as 16
S16= 2(16)^2+3(16)
= 512+48=560
S16 = n/2(a +An)
560=16/2(5+An)
560/8=5+An
70-5= An
An= 65
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