Question

the sum of first n terms of AP is given by Sn=2n²+3n find sixteenth term

Answer 1

A16=s16-s15
A16=2(16)2+3(16)
=512+48
=560.
A15=2(15)2+3(15).
=450+45
=495.
Now,
A16=560-495.
=65..