Question

The sum of first n terms of the series a, 3a, 5a, …….. is (a) na (b) (2n – 1) a (c) n²a (d) n²a²​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

AP is a,3a,5a,....

Here, a=a, (first term)

d=2a (common difference)

Sum =S

n

=n/2[2a+(n−1)d] , where n= number of terms

=n/2[2a+2an−2a]

=an

2

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