The sum of first six terms of Ap is 66 and the ratio between 3rd and 6th term is 3:7 find the AP
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S6 = 3(2a+5d)=66
Therefore,2a+5d=22.
...
a3/a6 = 3/7
=>7a3 = 3a6
=>7(a+2d) = 3(a+5d)
=>7a+14d =3a+15d
=>4a=d
.....
=>2a+20a=22a=22.
Hence,a=1.
Hence,d=4.
....
Hence,the AP:
1,5,9,13,17,21,25,..........
....
Hope this helps you.
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Therefore,2a+5d=22.
...
a3/a6 = 3/7
=>7a3 = 3a6
=>7(a+2d) = 3(a+5d)
=>7a+14d =3a+15d
=>4a=d
.....
=>2a+20a=22a=22.
Hence,a=1.
Hence,d=4.
....
Hence,the AP:
1,5,9,13,17,21,25,..........
....
Hope this helps you.
Follow my account for more instant answers.
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