The sum of first ter and fifth term of an ap is 26 and the product of the second term with fourth term is 160. find the sum of first 7 terms of this ap.
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first term x 2nd term x+y ; 3rd term x+2y ; 4th term x+3y ; 5th x+4y ; 6th x+5y ;7th x+6y SO according to the question x+(x+4y)=26 ...................(1) and (x+y)*(x+3y)=160 ...................(2) so from (1) we get 2x +4y=26 or x=26-4y/2...........(3) from (2) we get x^2 +3xy+xy+3y^2=160 ..........(4) NOW PLEASE SOLVE (3) AND (4) EQUATION and FIND THE VALUE OF x and y then for getting answer APPLY THIS :::::::::x+(x+y)+(x+2y)+(x+3y)+(x+4y)+(x+5y)+(x+6y) putting the value of x and y
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