The sum of first three terms is an arithmetic progression is 24 and the sum of their square is 224 find the first three terms of arithmetic progression
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Answer:4, 8, 12
Step-by-step explanation:
Sum of first three terms is three times the middle number, which is the second term
So the second term is 24/3=8
So the numbers can be written as 8-d, 8 and 8+d where d is the common diffu
Sum of squs is 224
So (8-d)^2 + 8^2 + (8+d)^2 =224
We know that (a-b)^2 + (a+b)^2=2(a^2+b^2)
So 2(8^2 + d^2) + 8^2 =224
2d^2 +192=224
2d^2= 32
d^2=16
d=+4 or -4
If d is 4, the terms are 4, 8 and 12
If d is -4, the terms are 12, 8 and 4
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