The sum of five consecutive integers is 35. Find the integers.
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Answered by
1
Answer:
let the no. be x , x+1 , x+2 , x+3 , x+4
x+x+1+x+2+x+3+x+4 = 35
x⁵+10=35
x⁵=35-10
x⁵=25
x=25/5
x=5
ans = 5,6,7,8,9
Answered by
9
Given:
- The sum of five consecutive integers is 35.
To find:
- The integers.
Solution:
• Let's use x in common of integers.
Here,
- Intergers :
- x
- x + 1
- x + 2
- x + 3
- x + 4
⠀⠀━━━━━━━━━━━━━━━━━━━⠀
« Now, Let's make an equation,
→ x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 35
→ 5x + 10 = 35
→ 5x = 35 - 10
→ 5x = 25
→ x = 25/5
→ x = 5
Therefore,
- x = 5
- x + 1 = 6
- x + 2 = 7
- x + 3 = 8
- x + 4 = 9
∴ Hence, The consecutive integers are 5,6,7,8,9.
⠀⠀━━━━━━━━━━━━━━━━━━━⠀
« Now, Let's verify this,
→ x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 35
→ 5x + 10 = 35
→ 5(5) + 10 = 35
→ 25 + 10 = 35
→ 35 = 35
LHS = RHS
- Hence, Verified!
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