the sum of five consecutive number is 2275, what is the sum of the larget and the smallest
Answers
Answer:
let the five consecutive numbers are x,x+1,x+2,x+3,x+4.
and their sum is 2275
now,
x+x+1+x+2+x+3+x+4=2275
5x+10=2275
5x=2275-10
5x=2265
x=2265/5
x=453.
Solution :-
Let us assume that, five consecutive number are x, (x + 1), (x + 2), (x + 3) and (x + 4) .
So,
→ Sum of five consecutive numbers = 2275
then,
→ x + (x + 1) + (x + 2) + (x + 3) + (x + 4) = 2275
→ 5x + 10 = 2275
→ 5x = 2275 - 10
→ 5x = 2265
→ x = 453
therefore,
→ Sum of the largest and the smallest = x + (x + 4) = (2x + 4) = 2 * 453 + 4 = 906 + 4 = 910 (Ans.)
Learn more :-
evaluate the expression given by 83 - 81 + 87 - 85 +__________ + 395 - 393 + 399 - 397
https://brainly.in/question/14081691
If the nth term of an AP is (2n+5),the sum of first10 terms is
https://brainly.in/question/23676839