Question

The sum of four consecutive integer is 1290. The greatest of them is.

Answer 1

Explanation:

let the integer be X

(X - l )+x + (X+1 )( X + 2 ) = 1290now remove X and constant and keep it aside

= 4x -1+1+2= 1290

=4x + 2= 1290

make constant to go opposite side

4x =1290-2

4x = 1288

again make constant to go opposite side

X = 1288 divided by 4

X = 322

now apply to all

322 -1=321

322+1=323

322+2=324

322=322

four consecutive numbers are 321,322,323,324

greatest is 324