Question

the sum of four consecutive numbers are 106. Find the numbers.

Answer 1

Answer:

Let the first no. be "a"

The second no.=a+1

Third no.=a+2

Fourth no.=a+3

ATQ the sum of no.s is 106

Therefore,(a)+(a+1)+(a+2)+(a+3)=106

Or,4a+6=106

Or,4a=100

Or,a=100/4=25

Therefore no.s are 25 ,26 ,27 and 28