Question

The sum of four consecutive numbers in an ap is 32 and the ratio of product of first and last no. To the product of two middle tier. I is 7:15 . Find the no.

Answer 1

Answer:

let the terms be

a-3d,a-d,a+d,a+3d

1-3d+a-d+a+d+a+3d=32

4a=32

a=8

a²-9d²/a²-d²=7/15

64-9d²/64-d²=7/15

15(64-9d²)=7(64-d²)

128d² = 512

d² = 512/128

d² = 4

d = 2

Four consecutive numbers are 2, 6, 10 and 14

Step-by-step explanation: