The sum of four consecutive numbers in an ap is 32 and the ratio of product of first and last no. To the product of two middle tier. I is 7:15 . Find the no.
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let the terms be
a-3d,a-d,a+d,a+3d
1-3d+a-d+a+d+a+3d=32
4a=32
a=8
a²-9d²/a²-d²=7/15
64-9d²/64-d²=7/15
15(64-9d²)=7(64-d²)
128d² = 512
d² = 512/128
d² = 4
d = 2
Four consecutive numbers are 2, 6, 10 and 14
Step-by-step explanation:
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