Question

The sum of four consecutive numbers in an ap is 32 and the ratio of the product of the first and last

Answer 1

Answer:

The question is incomplete.

Let first term is A

Common Difference= d

Four numbers are

A ,A+d,A+2d ,A+3d

ATQ

A+A+d+A+2d+A+3d=32

4A+6D=32

What value of A and d can satisfy this equation ????

A=5

D=2

1st number = 5

Last number= 5 +3×2

= 11

Ratio = 5:11