Question

the sum of four consecutive numbers in ap is 32 and the ratio of the product of the the first and last term to the product of two middle terms is 7:15 . find the number

Answer 1

let the numbers be (a+3d),(a+d),(a-d) and (a-3d)
a/c1
sum of numbers = 32
a=8
a/c2
$\frac{(a+3d) \times (a+d)}{(a - d) \times (a + - 3d)} = \frac{7}{15}$
Now, solve this by putting value of a=8 in this you get ,
$d = \sqrt{?} |$
solve it and find the AP
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