The sum of four consecutive odd numbers is 128. Find the numbers.
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0
Answer:
let the numbers be x, x+1, x+2, x+3
Step-by-step explanation:
a/q
x+x+1+x+2+x+3=128
4x+6=128
4x=122
x=61/2
Answered by
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Let the consecutive odd numbers be x ,2x , 3x,4x
X +2x+3x+4x=128
10x=128
X=128/10
X=64/5
X +2x+3x+4x=128
10x=128
X=128/10
X=64/5
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