The sum of four consecutive odd numbers is 80. Find the numbers.
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Answered by
3
let the consecutive odd numbers be 2x+1,2x+3,2x+5,2x+7
given sum=80
=>8x+16=80
=>8x=64
=>x=8
hence consecutive odd numbers are
2x+1=2(8)+1=17
similarly remaining number are 19,21,23
.
hence 17,19,21,23 are ur required numbers...
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hope this helps u..
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keep smiling
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mark this as brainliest
given sum=80
=>8x+16=80
=>8x=64
=>x=8
hence consecutive odd numbers are
2x+1=2(8)+1=17
similarly remaining number are 19,21,23
.
hence 17,19,21,23 are ur required numbers...
.
.
hope this helps u..
.
keep smiling
.
mark this as brainliest
ganeshnasrikripdvjr9:
plzz mark this as brainliest answer
Answered by
8
Let the numbers be x + 1, x + 3, x + 5 and x + 7
A/q,
x + 1 + x + 3 + x + 5 + x + 7 = 80
4x + 16 = 80
4x = 64
x =
x = 16
1st number = x + 1 = 16 + 1 = 17
2nd number = x + 3 = 16 + 3 = 19
3rd number = x + 5 = 16 + 5 = 21
4th number = x + 7 = 16 + 7 = 23
A/q,
x + 1 + x + 3 + x + 5 + x + 7 = 80
4x + 16 = 80
4x = 64
x =
x = 16
1st number = x + 1 = 16 + 1 = 17
2nd number = x + 3 = 16 + 3 = 19
3rd number = x + 5 = 16 + 5 = 21
4th number = x + 7 = 16 + 7 = 23
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