Question

The sum of four consecutive terms in an AP is 32 and the ratio of the product of the first and the last terms to the product of two middie terms is 7:15. Find the terms.

Pls help ​

Answer 1

Step-by-step explanation:

ANSWER

Let the four consecutive numbers in AP be (a−3d),(a−d),(a+d) and (a+3d)

So, according to the question.

a−3d+a−d+a+d+a+3d=32

4a=32

a=32/4

a=8......(1)

Now, (a−3d)(a+3d)/(a−d)(a+d)=7/15

15(a²−9d²)=7(a²−d²)

15a²−135d²=7a²−7d²

15a²−7a²=135d²−7d²

8a²=128d²

Putting the value of a=8 in above we get.

8(8)²=128d²

128d²=512

d²=512/128

d²=4

d=2

So, the four consecutive numbers are

8−(3×2)

8−6=2

8−2=6

8+2=10

8+(3×2)

8+6=14

Four consecutive numbers are 2,6,10and14

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Answer 2

Step-by-step explanation:

$\qquad \quad {:} \longrightarrow \sf{\sf{SP \: = \: 4500 \: + \: 540}}$

Answer 3

Step-by-step explanation:

$\qquad \quad {:} \longrightarrow \sf{\sf{SP \: = \: 4500 \: + \: 540}}$

Answer 4

Step-by-step explanation:

$\qquad \quad {:} \longrightarrow \sf{\sf{SP \: = \: 4500 \: + \: 540}}$

Answer 5

Step-by-step explanation:

$\qquad \quad {:} \longrightarrow \sf{\sf{SP \: = \: 4500 \: + \: 540}}$

Answer 6

Step-by-step explanation:

$\qquad \quad {:} \longrightarrow \sf{\sf{SP \: = \: 4500 \: + \: 540}}$