The sum of four consecutive terms of an A.P. is 2. The sum of 3rd and 4th terms is 11. Find the terms.
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Answer:
the terms are -7,-2,3
Step-by-step explanation:
a+a+d+a+2d+a+3d=2
4a+6d=2
also. a+2d+a+3d=11
2a+5d=11
so
d=5
a=-7
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