The sum of four numbers in A.P is 40.If the sum of the product of first and last tems and two middle terms is 160.find the numbers.
Plz solve the problem.
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Answer:
A.P.=10,12,14,16
Step-by-step explanation:
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(a-3d)+(a-d)+(a+d)+(a+2d)=40
a=10
(a-3d)(a+3d)+(a+d)(a-d)=160
d=2
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