The sum of four numbers in AP is 16
and the sum of their cubes is 446
Find the numbers.
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Answer:
Let the numbers be a-3d, a-d, a+d, a+3d
Sum =4a=16
a=4
(a-3d)^3+(a-d)^3+(a+d)^3+(a+3d)^3=496
4a^3 +60ad^2 =496
256+240d^2 =496
240d^2 =240
d^2 =1
d=1
Therefore the numbers are 1,3,5,7
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