Question

The sum of four numbers in AP is 16
and the sum of their cubes is 446
Find the numbers.​

Answer 1

Answer:

Let the numbers be a-3d, a-d, a+d, a+3d

Sum =4a=16

a=4

(a-3d)^3+(a-d)^3+(a+d)^3+(a+3d)^3=496

4a^3 +60ad^2 =496

256+240d^2 =496

240d^2 =240

d^2 =1

d=1

Therefore the numbers are 1,3,5,7