Question

the sum of four numbers in AP is 50 . The greatest number is four times the smallest number. Find those numbers.

Answer 1

Let the first term be a.

Let difference be d.

a+a+d+a+2d+a+3d=50

=4a+6d=50

=2a+3d=25.............(1)

The greatest number is 4 times the smallest

a+3d=4a

=3a=3d

=a=d

So inserting it in 1 we get:

=2d+3d=25

=5d=25

=d=25/5

=5

a=d=5

So

AP=a,a+d,a+2d,a+3d

AP=5,10,15,20

The AP can also be

=20,15,10,5

Hope I helped.

Answer 2

Step-by-step explanation:

Refers to the attachment....