the sum of how many teams of an AP: 7,11,15,19,23, ... will be 900 ?
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Answered by
2
A=7
d=11-7=4
An=900
=>n/2{2a+(n-1)d} =900
=>n/2{2×7+(n-1)4} =900
=>n/2{14+4n-4}=900
=>n/2{10+4n}=900
=>10n+4n^2=2×900
=>4n^2+10n-1800=0
now solve the above given equation and definitely u will get the answer
d=11-7=4
An=900
=>n/2{2a+(n-1)d} =900
=>n/2{2×7+(n-1)4} =900
=>n/2{14+4n-4}=900
=>n/2{10+4n}=900
=>10n+4n^2=2×900
=>4n^2+10n-1800=0
now solve the above given equation and definitely u will get the answer
Answered by
2
20 is ans for the question
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