The Sum of n terms of an AP: 1, 3, 5 , 7, 9, .... is ---- a) = (n / 2) [2a + (n - 1) d] b) = ( n / 2) [2a + (n + 1) d] c) = nx n +1 d) = nxn
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option d
here we consider number of terms= n
we can learn like sum all ( n) odd number is
n ✖ n
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