The sum of n terms of an ap is 2n^2+3n find the nth
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1st term of AP is 2+3=5
2nd term is 2*2^2 + 3*2 - 1st term = 14-5=9, common difference=4
Nth term of AP = 5 + (n-1)*4 = 5+4n-4 = 1+4n
2nd term is 2*2^2 + 3*2 - 1st term = 14-5=9, common difference=4
Nth term of AP = 5 + (n-1)*4 = 5+4n-4 = 1+4n
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