the sum of n terms of an ap is 5 n^2 /2 + 3n/2 Find its 38 value
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Hello dear,
Sn = (5n2 + 3n) / 2
Therefore, S₃₈ = [5 (38)2 + 3 (38) ] / 2
Thus S₃₈ = [ 7220+114] / 2 = 3667
S₃₇= [5 (37)2 + 3 (37)] / 2 =[ 6845+111]/ 2
=>(6956) 2 = >3478
Thus, S₃₇= 3478
Tn = Sn - Sn-1
Therefore, T₃₈ = S₃₈ - S₃₇
T₃₈ = 3667 - 3478= 189
Hope its help you dear :-)
Sn = (5n2 + 3n) / 2
Therefore, S₃₈ = [5 (38)2 + 3 (38) ] / 2
Thus S₃₈ = [ 7220+114] / 2 = 3667
S₃₇= [5 (37)2 + 3 (37)] / 2 =[ 6845+111]/ 2
=>(6956) 2 = >3478
Thus, S₃₇= 3478
Tn = Sn - Sn-1
Therefore, T₃₈ = S₃₈ - S₃₇
T₃₈ = 3667 - 3478= 189
Hope its help you dear :-)
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