The sum of n terms of an AP is given by Sn=2n^2+3n.find the 16th term of the AP
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Step-by-step explanation:
Given: Sn=2n²+3n
Put n=1
Sn=2(1)²+3(1)
S1=2+3=5
a=5
Put n=2
S2=2(2)²+3(2)
S2=8+6=14
a1+a2=s2
5+a2=14
a2=14-5
A2=9
d=a2-a1
d=9-5=4
a16=a+15d
a16=5+15(4)
a16=5+60
a16=65
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