the sum of n terms of an ap is n(5n-3). find the ap.
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Answered by
29
Heya user !!!
Here's the answer you are looking for
The sum of n terms or Sn = n (5n - 3)
So S1 = 1(5-3) = 2
Sum of one term means the first term itself that is a1
So a1 is 2
Now S2 = 2(10-3) = 14
S2 means sum of first 2 terms
So a1 + a2 = 14
a2 = 14 - a1 = 14 - 2 =12
a2 = 12
Also,
a2 = a1 + d
12 = 2 + d
d = 10
Thus the AP is 2, 12, 22, 32.....
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
The sum of n terms or Sn = n (5n - 3)
So S1 = 1(5-3) = 2
Sum of one term means the first term itself that is a1
So a1 is 2
Now S2 = 2(10-3) = 14
S2 means sum of first 2 terms
So a1 + a2 = 14
a2 = 14 - a1 = 14 - 2 =12
a2 = 12
Also,
a2 = a1 + d
12 = 2 + d
d = 10
Thus the AP is 2, 12, 22, 32.....
★★ HOPE THAT HELPS ☺️ ★★
yash288:
thank u very much
Answered by
9
Sn=n(5n-3)=5n^2-3n
5(1)^2-3(1)=1/2(2a+0d)
(5-3)2=2a
2*2=2a
a=2
d=10
2,12,22.......ap
5(1)^2-3(1)=1/2(2a+0d)
(5-3)2=2a
2*2=2a
a=2
d=10
2,12,22.......ap
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