Question

The sum of n terms of the series 2 + 6 + 10 + ....... is​

Answer 1

Answer:

Sn=n/2[2a+(n-1)d]

=n/2[2×2+(n-1)4]

=n/2(4+4n-4)

=n/2(4n)

=2n^2

Answer 2

sum = n/2 (2a+(n-1)d

= n/2(2×2+(n-1)4

=n/2 (4+4n-4)

= n/2 (4n)

= 2n^2 is the answer

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