The sum of n terms of two A.P's are 13-7n:3n+3 . Find ratio of second term?
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Sn/S'n=13-7n/3n+3
=n/2 {2.3+(n-1).(-7)}/n/2{2.3+(n-1).3}
now a/c to sum of Ap formula we arranged this like formula
tn/t'n={3+(n-1)(-7)}/{3+(n-1).3}
now ratio of second term
t2/t'2=(10-7x2)/3x2=-4/6= -2/3
=n/2 {2.3+(n-1).(-7)}/n/2{2.3+(n-1).3}
now a/c to sum of Ap formula we arranged this like formula
tn/t'n={3+(n-1)(-7)}/{3+(n-1).3}
now ratio of second term
t2/t'2=(10-7x2)/3x2=-4/6= -2/3
abhi178:
this time my net slow so I think ........
but you ask me where you confused I clear your doubt
actually answer given to the question i discussed is -4/5 in my notebook
how to took "a" as 3 for first A.P and also -7 for diffrence for first A.p
I think I my answer is right
answer is -2/3
yes i believe please explain what i have asked thanks for replying friend
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