The sum of n terms of two Ap are in the ratio 2n+3:6n+3 then the ratio of their 13th term is
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Let nth term of 1st A.P. = (2n+3)x Its 13th term will= (2×13+3)x =29x Let nth term kf 2nd A.P.= (6n+3)x Its 13th term = (6×13+3)x =81x Ratio of their 13th terms: 29x/81x =29/81
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