Question

the sum of nature number and its resiprocal is 50/7 find the number​

Answer 1

Answer:

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Answer 2

$</p><p></p><p>\sf Let \: the \: number \: be \: x \\ \\</p><p></p><p>\sf According \: to \: the \: question, \\ \\</p><p></p><p>$

$</p><p> \sf \rightarrow \quad x + \frac{1}{x} = \frac{50}{7} \\ \\ \sf \rightarrow \quad \frac{ {x}^{2} + 1 }{x} = \frac{50}{7} \\ \\ \sf \rightarrow \quad {x}^{2} + 1 = \frac{50x}{7} \\ \\ \sf \rightarrow \quad 7 {x}^{2} + 7 - 50x = 0 \\ \\ \sf \rightarrow \quad 7{x}^{2} - 50x + 7 = 0 \\ \\ \sf \rightarrow \quad {7x}^{2} - 49x - x + 7 = 0 \\ \\ \sf \rightarrow \quad 7x(x - 7) - 1(x - 7) = 0 \\ \\ \sf \rightarrow \quad (x - 7)(7x - 1) = 0 \\ \\ \sf x = 7 \quad or \quad x = \frac{1}{7} </p><p>$