The sum of nth term of an A.P. is 3n2 +2n, then find its 10th term.
Answers
Answered by
1
Answer:
59
Step-by-step explanation:
a10= s10-s9
a10= 3*(10)^2+2*10 -(3*(9)^2+2*9)
a10= 3*100+20-(3*81+18)
a10= 300+20-(243+18)
a10=320-(261)
a10= 59
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