the sum of number and reciprocal is 10/3fine the number
Answers
Answered by
7
Let required number is x,
x + 1/x = 10/3
x² + 1 = 10x/3
3x² - 10x + 3 = 0
3x² -9x - x + 3 = 0
3x(x - 3) -1(x - 3)=0
(x -3)(3x - 1) =>0
x = 3 or x = 1/3
Required number is 3 or 1/3
I hope this will help you
(-:
x + 1/x = 10/3
x² + 1 = 10x/3
3x² - 10x + 3 = 0
3x² -9x - x + 3 = 0
3x(x - 3) -1(x - 3)=0
(x -3)(3x - 1) =>0
x = 3 or x = 1/3
Required number is 3 or 1/3
I hope this will help you
(-:
Answered by
3
Hiii friend,
Let the number be X .
Reciprocal of X is 1/X.
According to question,
X + 1/X = 10/3
X²+1 = 10X/3
3(X²+1) = 10X
3X²+3 = 10X
3X²-10X +3 = 0
3X²-9X-X+3 = 0
3X(X-3) -1(X-3) = 0
(X-3) (3X-1) = 0
(X-3) = 0 OR (3X-1) = 0
X = 3 OR X = 1/3
Hence,
Number = X = 3
HOPE IT WILL HELP YOU...... :-)
Let the number be X .
Reciprocal of X is 1/X.
According to question,
X + 1/X = 10/3
X²+1 = 10X/3
3(X²+1) = 10X
3X²+3 = 10X
3X²-10X +3 = 0
3X²-9X-X+3 = 0
3X(X-3) -1(X-3) = 0
(X-3) (3X-1) = 0
(X-3) = 0 OR (3X-1) = 0
X = 3 OR X = 1/3
Hence,
Number = X = 3
HOPE IT WILL HELP YOU...... :-)
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