Question

The sum of number is 184.one third of the first number exceeds one seventh of another number by 8.find the numbers.

Answer 1

Let the first number be x and the second number be y.
now
x + y = 184.Lets take x=184-y.
A.T.Q
1x/3-1y/7=8
184-y/3 - y/7 = 8
7(184-y) - 3y /21 = 8
1288-7y - 3y = 168
1288-10y = 168
-10y = -1120
y=112.
x=184-y
184-112
=72(Ans)

Answer 2

Step-by-step explanation:

x + y = 184.Lets take x=184-y.

A.T.Q

1x/3-1y/7=8

184-y/3 - y/7 = 8

7(184-y) - 3y /21 = 8

1288-7y - 3y = 168

1288-10y = 168

-10y = -1120

y=112.

x=184-y

184-112

=72(Ans)

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