Question

The sum of numbers between 100 and 500 which are divisible by 6 is
​

Answer 1

$\textbf{To find:}$

$\text{The sum of numbers 100 and 500 which are divisible by 6}$

$\textbf{Solution:}$

$\text{The numbers divisible by 6 are}$

$\textbf{102,108,114,.............,498}$

$\text{This forms an A.P with a=102, l=498 and d=6}$

$\textbf{Number of terms}$

$=\dfrac{l-a}{d}+1$

$=\dfrac{498-102}{6}+1$

$=\dfrac{396}{6}+1$

$=66+1$

$=67$

$\textbf{The required sum}$

$=S_{67}$

$=\dfrac{n}{2}[a+l]$

$=\dfrac{67}{2}[102+498]$

$=\dfrac{67}{2}[600]$

$=67[300]$

$=20100$

$\therefore\textbf{The sum of numbers 100 and 500 which are divisible by 6 is 20100}$

Find more:

Find the sum of first 40 positive integers between 10 and 450 divisible by 6

https://brainly.in/question/15142087