Question

the sum of numenator and denomenator of a ftaction is 4 more than twice the numenator , if both are increased by 3 they are in the ratio 2:3 , determine the fraction...​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\mathfrak{\huge{AnSwEr}}$

Let the numerator and the denominator be x and y respectively.

The fraction turns out to be = $\sf{\frac{x}{y}}$

According to the question, the first equation formed will be :

x + y = 2x + 4

Solve this formed equation further:

=》 x - y + 4 = 0 ...(1)

According to the question, the second equation formed will be :

$\frac{x+3}{y+3} = \frac{2}{3}$

Solve this formed equation further:

=》 3x - 2y + 3 = 0 ...(2)

I'll use the Elimination method for solving these equations :-

Multiply (1) by 3 :-

=》 3x - 3y + 12 = 0 ...(3)

Now equate (1) and (3), you get :-

y = 9

Similarly, by further solving, you get:

x = 5

The fraction = $\sf{\huge{\frac{5}{9}}}$

Hope it Helps!