The sum of numerator and denominator fraction is 3 less than twice the denominator. If each of the numerator and denominator is decreased by 1fraction becomes 1/2. Find fraction
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Let numerator be 'x' and denominator be 'y'.
Now,
The sum of numerator and denominator of fraction is 3 less than twice the denominator.
Therefore,
x+y=2y-3
=>x-y+3=0.........(i)
If the numerator and denominator is decreased by 1 .
Therefore,
x-1/y-1=1/2
=>2(x-1)=1(y-1)
=>2x-y-1=0.......(ii)
From (i) and (ii)
x-y+3=2x-y-1
=>x=4
equation (i)
x - y + 3 =0
putting the value of x
4 - y + 3 =0
y = 7
Therefore, the fraction =3/7
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