Question

The sum of numerator and denominator of a fraction is greater by 1 than thrice the numerator is decreased by 1 then the fraction reduced to 1/3 find the fraction​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given:-

• The sum of the numerator and denominator of a fraction is greater by 1. Than thrice the numerator.
• If the numerator is decreased by 1 then the fraction reduces to 1/3.

To find:-

• Find the fraction..?

Solutions:-

• Let the numerator of the fraction be 'x' and the denominator of the fraction be 'y'.

So, the fraction will become.

Fraction = Numerator/Denominator = x/y

The sum of the numerator and denominator of a fraction is greater by 1. Than thruc the numerator.

=> x + y = 3x + 1

=> -1 = 3x - x - y

=> -1 = 2x - y

=> y = 2x + 1 .......(i).

If the numerator is decreased by 1 then the fraction reduces to 1/3.

=> x - 1/y = 1/3

=> 3(x - 1) = y

=> 3x - 3 = y

Putting the value y from Eq (i). in Eq (ii).

=> 3x - (2x + 1) = 3

=> 3x - 2x - 1 = 3

=> 3x - 2x = 3 + 1

=> x = 4

Putting the value of x in Eq (i).

=> 2x - y = -1

=> 2(4) - y = -1

=> 8 - y = -1

=> -y = -1 - 8

=> -y = -9

=> y = 9

So, fraction = x/y

=> 4/9

hence, the fraction is 4/9.