Question

The sum of numerator and denominator of a fraction is 18 and denominator increases by 2 then the fraction reduces to 1/3. find fraction. word problem of linear equation​

Answer 1

Answer:

Let the numerator be x & denominator be y..

x+y= 18.............(1)

x/y+2 =1/3

3x=y+2

x=(y+2)/3

put this value in eq 1

x+y=18

(y+2)/3+y=18

(y+2+3y= 18×3

4y+2 =54

4y=54-2

4y= 52

y= 52/4

y= 13

put the value of y in eq 1

x+y=18

x+ 13=18

x= 18- 13

x= 5

therefore x=5,y=13

Hence required fraction = x/ y = 5/13

Answer 2

Answer:

here's your answer

Step-by-step explanation:

Let the numer be x & denom be y..

x+y= 18.............(1)

x/y+2 =1/3

3x=y+2

x=(y+2)/3

put this value in eq 1

x+y=18

(y+2)/3+y=18

(y+2+3y= 18×3

4y+2 =54

4y=54-2

4y= 52

y= 52/4

y= 13

put the value of y in eq 1

x+y=18

x+ 13=18

x= 18- 13

x= 5

Hence req. fraction = x/ y = 5/13

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