Question

The sum of numerator and denominator of a fraction is 18 . If the denominator is increased by 2 ,the fraction reduced to 1/3.Find the fraction....


pls I have doubt on my answers...

pls solve it ☺️☺️

Answer 1

Hey ^_^

Let the numerator br x and denominator be y

According to question

x + y = 18
x = 18- y


x/y+2 = 1/3
18-y /y+2 = 1/3

(18-y )3 = y+2
54 - 3y = y+2
52 = 4y
y = 13

x = 18 -13
x = 5

Therefore , the fraction is ---

✴ 5/13 ✴

✌✌ Hope this helps

Answer 2

Let the numerator be x and the denominator be y and the fraction be x/y

Given that the sum of numerator and denominator = 18
Therefore
x + y = 18 (equation 1)

If the denominator is increased by 2, the fraction is reduced to 1/3
i.e   x/(y+2) = 1/3
3x = y + 2
3x - y = 2 (equation 2)

Adding equation 1 and 2
x + y = 18
3x - y = 2

4x = 20
x = 5

x + y = 18
5 + y = 18
y = 13

The fraction is x/y = 5/13